Passing variables into a single array in a function?

MrPickle · #1 (**permalink**) 05-17-2008, 10:05 AM

How would you pass variables into an array in a function?

For example: void Function(int Array[0, 1, 2, 3, 4])
then calling Function(0, 3, 7, 1, 3); would set Array[0] to 0, Array[1] to 3, etc...

I know that doesn't work because I tried it but how would you do something similar or do you have to put the variables into an array before hand and do: void Function(int Array[]);
Function(Array[5]);

HelloWorld · #2 (**permalink**) 05-19-2008, 10:22 AM

What about

Code:

Function(int[] myArray);

that should work..

MrPickle · #3 (**permalink**) 05-19-2008, 03:47 PM

Quote:

Originally Posted by HelloWorld

What about

Code:

Function(int[] myArray);

that should work..

I know how to parse arrays, I wanted to know whether you could pass individual variables straight into an array.

HelloWorld · #4 (**permalink**) 05-20-2008, 04:58 PM

Quote:

Originally Posted by MrPickle

I know how to parse arrays, I wanted to know whether you could pass individual variables straight into an array.

Ermm... I seriously don't get on what are you trying to do, you're trying to pass an individual variable straight into array? what does that mean? You're passing variable to element of an array? Remember, array is just collection of variables!

MrPickle · #5 (**permalink**) 05-21-2008, 09:45 AM

Quote:

Originally Posted by HelloWorld

Ermm... I seriously don't get on what are you trying to do, you're trying to pass an individual variable straight into array? what does that mean? You're passing variable to element of an array? Remember, array is just collection of variables!

I want to pass the variables straight into an array in a function eg;

calling Function(1, 3, 2, 1, 0);
then they would be put straight into an array in Function's arguments.

HelloWorld · #6 (**permalink**) 05-21-2008, 02:34 PM

something like..

Code:

Function (int a, int b, int c, int d, int e)
    x[0] = a;
    x[1] = b;
    x[2] = c; // ... and so on

???

Bench · #7 (**permalink**) 05-21-2008, 05:32 PM

Its still not entirely clear to me what exactly you want to do - Are you trying for array initialisation?

Code:

int my_arr[] = { 1, 2, 3, 4, 5, 6, 7 };

MrPickle · #8 (**permalink**) 05-22-2008, 08:58 AM

It's hard to explain. I want to know if it's possible to put pass variables, straight into an array that is the argument of a function. Argh, that doesn't explain it.

If I declared a function like:

Code:

void MyFunction(int MyArray[]){}

Could you pass individual variables straight into that array without assigned them to an array before passing them to the function.

Maybe this explains things:

Code:

#include <iostream>
using namespace std;

void MyFunction(int MyArray[]){
   cout << MyArray[0] << endl;
   cout << MyArray[1] << endl;
   cout << MyArray[2] << endl;
}

int Main(){
   MyFunction({1, 4, 6}); //Something or another
   return 0;
}

Output:

Quote:

1
4
6

Bench · #9 (**permalink**) 05-22-2008, 09:57 AM

No, that's not possible, since a function will only accept an array parameter by way of a pointer-to its first element. a pointer is an address in memory, which implies that an array must already exist in memory before you may pass it to a function.

Perhaps you could give a broader view of the problem you're trying to solve, and someone might be able to suggest how to deal with it.

MrPickle · #10 (**permalink**) 05-22-2008, 03:27 PM

It wasn't a problem, I was just curious to as how you could do it if it's possible. My assumption was that you'd already have to have an array defined.

Thanks.

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