Java Error

nogono · #1 (**permalink**) 09-04-2007, 06:05 PM

Below is my program....i am able to input the array...but i am unable to display it.......In second file...i made comment...where i think is th error..

Main file:

public

class add implements name {

input vl;

public add()
{

vl=new input();

}

publicvoid display(int dis)
{
System.out.println("Displaying");

System.out.println(dis);
}

publicstaticvoid main(String[] args)
{
new add();
}

}

Second File:

import

java.io.*;

public

class input {

int[] num=newint[10];
name mas;

public input()
{
int nu12=0;

for(int i=0;i<num.length;i++)
{

System.out.println("Numbers Entered [ " + i + " ] = ");

BufferedReader in=new BufferedReader(new InputStreamReader(System.in));

try {
nu12=(Integer.parseInt(in.readLine()));
System.out.println("Passing thru array");
mas.display(nu12);//This line is not executing why so...

} catch (NumberFormatException e) {} catch (IOException e) {} catch(NullPointerException e){}

}

}

}

Interface file:

public

interface name {

void display(int dis);

}

HelloWorld · #2 (**permalink**) 09-04-2007, 09:50 PM

How do you want to read the input from the user? Is it from the command line? From a file or what? If it's a command line input, I'd suggest you to just use Scanner class... It's the same thing, but it's make your code looks nicer lol...

and then use this method:

Quote:

String nextLine()
Advances this scanner past the current line and returns the input that was skipped.

Code:

import java.util.Scanner;

public class Test {
  public static void main(String[] args) {
    Scanner s = new Scanner();
    int[] num = new int[10];
    int cnt = 0;
    while (cnt < num.length) {
      System.out.print("Enter number: ");
      String number = s.nextLine();
      int[cnt] = Integer.parseInt(number); // you need to add try.. catch.. block
      System.out.println(int[cnt]);
    }
  }
}

let me know if it works lol.. I didn't test it

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